Same amount of electricity is passed through the solutions of HCl and CuSO4. If 6.35 g of copper is deposited from CuSO4 solution, the amount of hydrogen liberated at STP will be
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a
0.01
b
0.1
c
0.001
d
1
answer is B.
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Detailed Solution
From Faraday's second law, wH2wCu=EH2ECu⇒wH2=163.5×6.35=0.1g