A sample of ammonia phosphate, (NH4)3PO4 contains 6.36 moles of H-atoms. The number of moles of O-atom in the sample is (Atomic mass of N = 14.04,H = 1, P = 3 1 and O = 16)
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a
0.265
b
0.795
c
2.12
d
4.14
answer is C.
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Detailed Solution
∴12 moles of H-atoms =1 mole of NH43PO4∴ 1 mole of H-atom =112 mole of NH43PO4∴6.36 moles of H-atom =112×6.36 =6.3612 mole of NH43PO41 mole of NH43PO4=4 moles of oxygen So, 6.3612 mole of NH43PO4=4×6.3612=2.12 mol