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Q.

A sample of calcium carbonate (CaCO3) has the following percentage composition: Ca = 40%; C= 12%; O=48%, If the law of constant proportions is true, then the weight of calcium in 4 g of a sample of calcium carbonate from another source will be

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a

0.016 g

b

0.16 g

c

1.6 g

d

16 g

answer is C.

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Detailed Solution

According to law of constant proportions the weight ratio of elements combines to form certain compound is always fixed irrespective of the source from which the compound is obtained.40% of 'Ca' is present in CaCO3

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