A sample of charcoal weighing $$0.6$$ g was brought into contact with a gas contained in a vessel of $$100$$ mL capacity at $$300$$ K. The pressure of the gas was found to fall from $$70$$ torr to $$40$$ torr. Calculate the volume of the gas (reduced$$ to $$STP) that is adsorbed per gram of the adsorbent under the condition of the experiment. (Volume$$ of the charcoal is $$negligible)

Question

Infinity Learn · Accepted Answer

Initial                       Final $$p1=70$$ torr           $$p2=40$$ torr $$V1=100mL$$           $$V2=$$?$$T1=300K$$            $$T2=300K$$∴    $$p1V1T1=p2V2T2$$    $$V2=p1V1p2=7040$$×$$100=175mLVolume$$ of the vessel $$=$$ $$100$$ mlL Volume of the gas adsorbed $$=$$ $$175-100$$ $$=$$ $$75$$ mL Volume of the gas adsorbed per gram of charcoal.$$=750.6=125$$ $$mL/gThis$$ volume is reduced to STP Final  STP $$p2V2T2=p3V3T340$$×$$125300=760$$×$$V3273$$∴$$V3($$ at STP $$)=40$$×$$125$$×$$273300$$×$$760=6.0mL$$

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