A sample of ideal gas (γ=1.4) is heated at constant pressure. If 140J of heat is supplied to gas then work and ∆E will be

Given γ = 1.4  gas is diatomic ∴CV=52R;Cp=7R2 Given ΔH=140J ΔH=nCpΔT 140=n×7R2×ΔT ΔT=40nR Now W=−nRΔT =−n×R×40nR =−40J ∴according to first law ΔE=Q+W =140−40 =100J