A sample of pure sodium carbonate 0.318 g is dissolved in water and titrated with HCI solution. A volume of 60 mL is required to reach the methyl orange end point. Calculate the molarity of the acid.

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away

An Intiative by Sri Chaitanya

0.1 M

0.2 M

0.4 M

None of these

answer is A.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Na2CO3+2HCl⟶2NaCl+H2O+CO2At the equivalent point m.mole of HCl =2 x m.mole of Na2CO360×M=2×0.318106×1000Mw of Na2CO3=106M=0.1

Watch 3-min video & get full concept clarity