For a saturated solution of AgCl at 25°C, specific conductance 3.41 × 10-6 ohm-1 cm-1 and of water used for preparing. The solution is 1.60 × 10-6 ohm-1 cm-1. If λAgCl∞ = 138.3 ohm-1 cm2 eq-1, the Ksp of AgCl is 0.17 × 10-x M2.The value of x is

For AgCl, molarity = normality κ=3.41×10−6−1.6×10−6=1.81×10−6Ω−1cm−1For saturated solution of sparingly soluble salt,λV=λ∞  and   solubility = normality ∴ λV=λ∞=1000×Ks∴ s=1000×Kλ∞=1000×1.81×10−6138.3=1.31×10−5 Now, Ksp(AgCl)=s2=1.31×10−52=0.1716×10−9∴ x=9