First slide

Gaseous state

Question

A sealed container with gas at 2.00 atm is heated from 20.0 K to 40.0 K. The new pressure is

Moderate

A

0.50 atm
B

1.00 atm
C

4.00 atm
D

2.14 atm

Solution

Since, volume is constant
$\frac{p_{2}}{p_{1}} = \frac{T_{2}}{T_{1}}, p_{2} = 2 \times \frac{40}{20} = 4 atm$

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