For a second diffraction using X-ray Bragg's equation, for a crystal with separation between two layers as d Ao, following graphical study was observed when varying θ at different λ.What is the value of d?
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a
4.0 Ao
b
0.6020 Ao
c
0.3010 Ao
d
2.0 Ao
answer is D.
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Detailed Solution
By using Bragg's equation,nλ=2dsinθ where, n=2 (2nd diffraction) λ=dsinθ or logλ=logd+logsinθd is constant (distance between two planes) as θ changes, λ also changes.When θ = 90°, sin = 90° = 1, hence log sin 90° = 0OX = 0.3010 Ao∴ log λ = 03012 Ao ∴ λ = 2.0 Ao