Transition elements

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By Expert Faculty of Sri Chaitanya
Question

This section contains questions each with two columns-I and II. Match the items given in column I with that in column II.

 

 

Column I Column II
a.Nip.Elements having same number
of unpaired electron in their
dispositive in column I
b.Naq.At least 13 electrons are having
magnetic quantum number 'zero'
c.Mnr.Atom is paramagnetic
d.Pds.Element is not transition element
  t.Element having pseudo inert gas
configuration in its dispositive cation
 

Moderate
Solution

a-p;q;r,b-r;s,c-q;r,d-p;q

(a) p, q, r:

(q) m =0 present in all orbitals
2 + 2 + 2 + 2 + 2 + 2 + I = 13 (minimum)
(r) Atom is paramagnetic. (It is a transition element.)

(b) r, s;

(r) Na (Z = ll) = 1s2 2s2 2p6 3s1 (n - l)
Na2+ = 2p5 (n = l)
Number of unpaired electron in Na2+ = I
m =0 (present in all orbitals.)
2+2+2+l = 7(minimum)

(s) Atom is paramagnetic. (It is not a transition element.)

(c) q, r;

Mn(Z=25)=1s22s22p63s23p64s23d5

Mn2+=3d5

m = 0 (present in all orbitals.)
m = 2+2+2+2+2+2+ 1= 13
Number of unpaired electron in Mn2+ = 5
Atom is paramagnetic.
It is a transition element

(d) p, q

Pd(Z=46)=1s22s22p63s23p64s23d104p65s24d8

Pd2+=4d8

Number of unpaired electron in Pd2+ = 2

m = 0 present in all orbitals.

m = 2+2+ 2+ 2+2+ 2+2+2+ 2+ 1 = 19

Atom is diamagnetic.
It is a transition element.


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