Q.
Select the correct statement (s) out of the following.
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a
PH+POH=14
b
PKw=14
c
Ka×Kb=Kw
d
All of these
answer is D.
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Detailed Solution
Kw=[H+][OH-]=10-14 -log{[H+][OH-]}=-log(10-14) -log(H+)-log(OH-)=14 PH+POH=14=PKw Similarly PKw=Pka+Pkb Ka×Kb=KwWhere, Kw=Ionic product of water Ka=Acid dissociation constant Kb=Base dissociation constant.
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