Q.
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By Expert Faculty of Sri Chaitanya
a
HC≡CH+2Naexcess→N⊕aCΘ≡CΘN⊕a+H2
b
HC≡CH+2Liexcess→LiCΘ≡CΘLi⊕+H2
c
HC≡CH+2NaNH2→N⊕aCΘ≡CΘN⊕a+2NH3
d
HC≡CH+2Kexcess→K⊕CΘ≡CΘK⊕+H2
answer is 2.
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