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a
Among Li⊖ and Be⊖,Be⊖ is most unlikely to exist.
b
The period number and group number of any representative element(s) are same, then elements in their ground state has the possible value of n = 2,1 = 0
c
Amongst Mn, Be, Rb and Tl, Rb is most electropositive (metallic) in nature
d
If there are three possible value −12,0,+12 for the spin magnetic quantum number m2 , then there will be 15 elements in the second period of the periodic table.
answer is D.
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Detailed Solution
1) e−+Be2s2⟶B⊖2s22p1 (It is difficult to add e−in the higher 2p orbital). Thus unlikely to exist. e−+Li2s′⟶Li2s2⊖e−can be added to same energy level 2sorbital) 2) 3) ) Rb (Alkali metal) is most electropositiveCorrect (4) 12 elements.For, n = 2.⇒ 12 Elements