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Q.

The shape of a molecule is determined by electron-pair repulsions in the valence shell. A lone pair occupies larger space than a bond pair because it is not shared by two nuclei. Thus the lone pair-lone pair repulsion is greater than the lone pair-bond pair repulsion, which in turn is greater than the bond pair-bond pair repulsion. The presence of lone pairs causes distortion of bond angles and hence a deviation from an ideal shape. The extent of distortion depends upon the orientation of the lone pairs around the central atom. In a trigonal bipyramid, the lone pairs occupy equatorial positions than the apical ones. In ABn type molecules, as the electronegativity of A increases, the bond pairs come closer and the repulsion between them increases. On the other hand, as electronegativity of B increases, the bond pairs get farther and repulsion decreases. Which of the following statements is true?The shape of which of the following molecules will not be distorted?Which of the following species will have the lone pair effects cancelled and have Linear shape?

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answer is [OBJECT OBJECT], [OBJECT OBJECT], [OBJECT OBJECT].

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Detailed Solution

F-O-F bond angle is 102, H-O-H bond angle is 104.The shape is tetrahedral and they is resonance in the molecule.ICl2− : In this molecule the central Iodine exhibits sp3d hybridization and having 3 lone pair of electrons. Those three lone pair of electrons occupy its equatorial position.All the 3 lone pairs are cancelled by each other.  All are separating by 120° Angle.
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