The silver ion in a solution is precipitated by addition of chloride ion. The final volume of solution is 500 mL. What should be the concentration of Cl- ion if not more than 0.10 mg of Ag+ ion remains unprecipitated?( Ksp(AgCl) = 1.0 x 10-10 )
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a
5.4×10−5M
b
1.9×10−6M
c
5.4×10−4M
d
1.9×10−7M
answer is A.
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Detailed Solution
Ag+=0.1mg=0.1×10−3g in 500mLH2O =0.1×10−3108mol in 500mLH2O =0.1×10−3×2108mol in 1LH2O =1.85×10−6M Ag+Cl−=1.0×10−10 ∴ Cl−=1.0×10−101.85×10−6 =5.4×10−5M