In SN2, solvolysis of RX in which the solvent is a nucleophile, what is the order and molecularity of the reaction?
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a
First order; unimolecular
b
First order; bimolecular
c
Second order; bimolecular
d
Pseudo first-order; bimolecular
answer is D.
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Detailed Solution
SN2 solvolysis reaction is bimolecular and the rate law is:Rate - K[RX][Solvent]Since the concentration of the solvent is very large and exceeds the amount of RX, therefore, its concentration is constant. Hence the reaction will follow pseudo first-order rate law.