Q.

SO2 and TeO2 act as respectively are

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a

reducing and reducing

b

reducing and oxidising

c

oxidising and oxidising

d

oxidising and reducing

answer is B.

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Detailed Solution

Oxidation number of sulphur changes from 0 to +4. Due to presence of d-orbitals (vacant) sulphur can extend its covalency and oxidation states till +6, which is stable in sulphur (eg: SF6​).Hence it acts as a reducing agent.Oxidation number of the Tellurium  changes from 0 to +4. Unlike sulphur,  Te  cannot show +6 oxidation state as it is highly unstable due to inert pair effect. Therefore, Te  can only show a decrease in its oxidation state (it can decrease to -2, +2). Hence, it acts as an oxidizing agent.
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SO2 and TeO2 act as respectively are