SO2 and TeO2 act as respectively are

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reducing and reducing

reducing and oxidising

oxidising and oxidising

oxidising and reducing

answer is B.

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Detailed Solution

Oxidation number of sulphur changes from 0 to +4. Due to presence of d-orbitals (vacant) sulphur can extend its covalency and oxidation states till +6, which is stable in sulphur (eg: SF6).Hence it acts as a reducing agent.Oxidation number of the Tellurium changes from 0 to +4. Unlike sulphur, Te cannot show +6 oxidation state as it is highly unstable due to inert pair effect. Therefore, Te can only show a decrease in its oxidation state (it can decrease to -2, +2). Hence, it acts as an oxidizing agent.

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