First slide

Conductors, semi conductors and insulators

Question

Sodium metal in liquid ammonia is

Easy

A

an ionic conductor
B

an electronic conductor
C

a mixed conductor
D

non - conductor

Solution

${M_{\left( g \right)}} \to M_{\left( g \right)}^ + + {e^ - }\,\,\left( {M = Alkalim etal} \right)$

${M^ + } + xN{H_3} \to M{\left( {N{H_3}} \right)_x}^{+}$
${e^ - } + yN{H_3} \to e{\left( {N{H_3}} \right)^ - }$
Adding all three equations
${M_{\left( g \right)}} + \left( {x + y} \right)N{H_3} \to M{\left( {N{H_3}} \right)_x}^ + + e\left( {N{H_3}} \right)_y^ -$
The solution is containing free ammoniated cation and free ammoniated electrons.Conductance is due to free ions and free electrons. Hence is a Mixed conductor.

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App