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Sodium on reaction with propyne formed compound ‘A’. Compound ‘A’ on reaction with secondary alkyl halide formed compound ‘B’. the molecular weight of the compound ‘B’ is 82. Find the alkyl halide among the following. 

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a
1–chlorobutane
b
2–chlorobutane
c
2–chloropropane
d
1–chloropropane

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detailed solution

Correct option is C

2–chloropropane on reaction with secondary alkyl halide formed 4–methyl-pent–2–yne (molecular weight: 82). So, the alkyl halide must be 2–halo propane.

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