A soft drink was bottled with a partial pressure of $$CO2$$ of $$3$$ bar over the liquid at room temperature. The partial pressure of $$CO2$$ over the solution approaches a value of $$30$$ bar when $$44g$$ of $$CO2$$ is dissolved in $$1$$ kg of water at room temperature. The approximate pH of the soft drink is $$______$$×$$10$$−$$1(First$$ dissociation constant of $$H2CO3=4.0$$×$$10$$−$$7$$;$$log2=0.3$$; density of the soft drink $$=1$$ g mL−$$1)$$

Question

A soft drink was bottled with a partial pressure of $$CO2$$ of $$3$$ bar over the liquid at room temperature. The partial pressure of $$CO2$$ over the solution approaches a value of $$30$$ bar when $$44g$$  of $$CO2$$  is dissolved in $$1$$ kg of water at room temperature. The approximate pH of the soft drink is $$______$$×$$10$$−$$1(First$$ dissociation constant of $$H2CO3=4.0$$×$$10$$−$$7$$;$$log2=0.3$$; density of the soft drink $$=1$$ g  mL−$$1)$$

Infinity Learn · Accepted Answer

Herny’s law : $$-$$ ωg∝$$P(for$$ $$1$$ kg of $$ssolvent)In$$ $$100rg$$  of  $$H2O$$ω$$g1$$ω$$g2=P1P2$$ ⇒Δ$$4$$ω$$=303$$⇒ω$$=4.4g$$ of ω$$2=0.1$$ moles of $$CO2$$ Wt. of solution $$=1000+4.4=1004.4g$$∴Vsol $$=1004.41=1004.4ml=1.0044l$$∴$$CO2=0.11.0044$$≃$$0.3M=H2CO3H2CO3$$⇌$$KalH++HCO3$$−$$H+=Ka1$$×$$C=4$$×$$10$$−$$7$$×$$10$$−$$1=2$$×$$10$$−$$4PH=$$ $$--log$$ (H+)

Best Courses for You

Detailed Solution

courses

Get Expert Academic Guidance – Connect with a Counselor Today!