First slide

Solubility product(KSP)

Question

Solubility of AgCl at 20⁰C is 1.435 × 10^–3g per litre. The solubility product of AgCl is

Easy

Solution

Solubility is generally expressed in terms of moles per litre, $\large S = \frac{{1.435 \times {{10}^{ - 3}}}}{{143.5}} = {10^{ - 5}}$
Solubility product, $\large {K_{sp}} = S \times S = {10^{ - 10}}$

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