The solubility of AgCl in 0.1M NaCl is (Ksp of AgCl = 1.2 × 10–10)

Solubility of AgCl will be suppressed in presence of NaCl due to commonion effect and the following equilibria gets established.AgCl(s)⇌AgClS'(aq)→Ag+S'(aq)+C '-S+0.1(aq)NaCl→Na+(aq)+Cl-0.1(aq)Ksp=S'+0.1×S'⇒1.2×10-10=10-1×S'⇒S'=1.2×10-9