First slide

Solubility product(KSP)

Question

Solubility of ${BaF}_{2}$ in a solution of $Ba {({NO}_{3})}_{2}$ will be represented by the concentration term

Easy

A

$[{Ba}^{2 +}]$
B

$[F^{-}]$
C

1/2 $[F^{-}]$
D

$2 [{NO}_{3}^{-}]$

Solution

Let S is the solubility of ${BaF}_{2}$ in solution of $Ba {({NO}_{3})}_{2}$
Then $K_{SP} = [{Ba}^{2 +}] {[F^{-}]}^{2}$
Then $[F^{-}] = 2 S;$
Then $\frac{1}{2} [F^{-}] = S$

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