The solubility of CdSO4 in water is 8.0×10−4mol L−1. Its solubility in 0.01 M H2SO4 solution is __________ ×10−6mol L−1,(Round off to the Nearest Integer)(Assume that solubility is much less than 0.01 M)

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answer is 64.

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Detailed Solution

Ksp=Cd2+SO4−2=S2=8×10−42=64×10−8M2,CuSO4=SO4−2=10−2M[S]=Cd2+=KspSO4−2=64×10−810−2=64×10−6

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