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Q.

Solubility of calcium phosphate (molecular mass, M) in water is W g per 100 mL at 250C. Its solubility product at 250C will be approximately

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a

109 WM5

b

107 WM5

c

105 WM5

d

103 WM5

answer is B.

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Detailed Solution

S =M= 10 WM  mol/L Ca3(PO4)2⇌3Ca+2+2PO4-2                       3s           2s KSP of Ca3 PO42 = 108 S5 = 108 10WM5 = 107 WM5   approximately
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