First slide

Solubility product(KSP)

Question

The solubility of calcium phosphate in water is x mol L^-¹ at 25⁰C. Its solubility product is equal to

Easy

A

108x²
B

36x³
C

36x⁵
D

108x⁵

Solution

$\large \\S_{C{a_3}{{\left( {P{O_4}} \right)}_2}}=x\\\\C{a_3}{\left( {P{O_4}} \right)_2}\left( s \right) \rightleftharpoons \mathop {C{a_3}{{\left( {P{O_4}} \right)}_2}\left( {aq} \right)}\limits_S \to \mathop {3C{a^{ + 2}}\left( {aq} \right)}\limits_{3S} + \mathop {2PO_4^{ - 3}\left( {aq} \right)}\limits_{2S}$

$\large \\S_{C{a_3}{{\left( {P{O_4}} \right)}_2}}=x\\\\C{a_3}{\left( {P{O_4}} \right)_2}\left( s \right) \rightleftharpoons \mathop {C{a_3}{{\left( {P{O_4}} \right)}_2}\left( {aq} \right)}\limits_S \to \mathop {3C{a^{ + 2}}\left( {aq} \right)}\limits_{3S} + \mathop {2PO_4^{ - 3}\left( {aq} \right)}\limits_{2S}\\\\K_{sp} = {\left( {3S} \right)^3} \times {\left( {2S} \right)^2} = 108{\text{ }}{S^5}{\text{ = 108 }}{{\text{x}}^5$

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