First slide

Solubility product(KSP)

Question

The solubility of Ca(OH)₂ in water is 6 ×10^–6M. The solubility of Ca(OH)₂ in a buffer solution of pH = 10 is

Easy

A

3.5 × 10^–10M
B

8.64 × 10^–8M
C

2.26 × 10^–6M
D

1.8 × 10^–2M

Solution

Let the solubility of Ca(OH)₂ in a buffer of P^H = 10 be S
$Ca (OH)_{2} (s) ⇌ \underset{s}{Ca (OH)_{2}} (aq) \to \underset{s}{{Ca}^{+}} (aq) + 2 \underset{2 S + 10^{- 4}}{({OH}^{-}) (a} q$ )
$K_{sp} = S^{'} {(2 S^{'} + 10^{- 4})}^{2} = 4 \times S^{3}$
$\Rightarrow S^{'} \times 10^{- 8} = 4 \times 6 \times 6 \times 6 \times 10^{- 18}$
$\Rightarrow S^{'} = 8.64 \times 10^{- 18}$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App