The solubility of N2 in water at 300 K and 500 torr partial pressure, is 0.01g L-1 .The solubility in (g L-1) at 750 torr partial pressure is

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0.02

0.015

0.0075

0.005

answer is B.

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Detailed Solution

According to Henry's law, p1p2=s1s2[p1 and p2 are partial pressures and s1 and s2 are solubilities]500750=0.01s2⇒s2=750×0.01500=0.015gL−1

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