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Q.

Solubility product of AB, AB2and AB3 are 4 ×10-12 , 4 ×10-12and 2.7 ×10-15 respectively.Correct order of solubility is

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a

S1 < S2 < S3

b

S1

c

S1=S2=S3

d

S1=S2>S3

answer is B.

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Detailed Solution

AB....S12 =4×10-12AB2....4S23=4×10-12AB3....27S34=27×10-16S1=2×10-6M ; S2 =10-4 M; S3 = 10-4;
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