The solubility product of Ca(OH)2 is x 3,if its solubility is 3,then the value of x is
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answer is 12.
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Detailed Solution
In aqueous solution, Ca(OH)2 is represented asCa(OH)2⇌Ca2++2OH−SmolL−1SmolL−1 Let the solubility of Ca(OH)2 be SmolL−1. Ksp=Ca2+OH−2=S⋅(2S)2=4S3 Given, solubility, S=3 On substituting value of S, we get Ksp=4(3)3=4×33=123