First slide

Solubility product(KSP)

Question

The solubility product of chalk is $9.3 \times 10^{- 8} .$ Calculate its solubility in gram per litre

Moderate

A

0.3040 gram/litre
B

0.0304 gram/litre
C

2.0304 gram/litre
D

4.0304 gram/litre

Solution

${CaCO}_{3} ⇌ {Ca}^{2 +} + {CO}_{3}^{2 -}$
Let the solubility of ${CaCO}_{3}$ be s mole per litre
$∴ K_{SP} = [{Ca}^{2 +}] [{CO}_{3}^{2 -}] = s . s .$
$∴ s = \sqrt{K_{SP}} = \sqrt{9.3 \times 10^{- 8}} = 0.000304 mole / litre$
Solubility in g/L = mole/litre x Molecular weight of ${CaCO}_{3}$
= 0.000304 x 100 = 0.0304 gram/litre

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