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Q.

The solubility product of chalk is 9.3 × 10-8. Calculate its solubility in gram per litre

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a

0.3040 gram/litre

b

0.0304 gram/litre

c

2.0304 gram/litre

d

4.0304 gram/litre

answer is B.

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Detailed Solution

CaCO3 ⇌ Ca2+ + CO32-Let the solubility of CaCO3 be s mole per litre∴ KSP = Ca2+ CO32- = s.s.∴ s= KSP = 9.3 × 10-8 = 0.000304 mole/litreSolubility in g/L = mole/litre x Molecular weight of CaCO3 = 0.000304 x 100 = 0.0304 gram/litre

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