Q.

The solubility product of chalk is 9.3 × 10-8. Calculate its solubility in gram per litre

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a

0.3040 gram/litre

b

0.0304 gram/litre

c

2.0304 gram/litre

d

4.0304 gram/litre

answer is B.

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Detailed Solution

CaCO3  ⇌  Ca2+  +  CO32-Let the solubility of  CaCO3  be s mole per litre∴     KSP = Ca2+   CO32- = s.s.∴  s=   KSP =  9.3 × 10-8 = 0.000304  mole/litreSolubility in g/L = mole/litre x Molecular weight of CaCO3 = 0.000304 x 100 = 0.0304 gram/litre
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