Q.

The solubility product (Ksp) of solid barium sulphate at 298 K is 1.1×10-10. The molar solubility, (S ) of  Ba2+ and SO42- are

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a

1.05×10-7 mol L-1

b

1.05×10-10 mol L-1

c

1.05×10-6 mol L-1

d

1.05×10-5 mol L-1

answer is D.

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Detailed Solution

BaSO4(s)⇌∴in water  Saturated solution Ba2+(aq)+SO42-(aq) If molar solubility is S, then 1.1×10-10=(S)(S)=S2or,        S=1.05×10-5Thus, molar solubility of barium sulphate will be equal to 1.05×10-5 mol L-1
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