First slide

Solubility product(KSP)

Question

The solubility product $(K_{sp})$ of the sparingly soluble salt MX at $25^{0} C is 2.5 \times 10^{- 9} .$ The solubility of the salt (in mol $L^{- 1})$ at this temperature is

Easy

A

$1.0 \times 10^{- 14}$
B

$5.0 \times 10^{- 8}$
C

$1.25 \times 10^{- 9}$
D

$5.0 \times 10^{- 5}$

Solution

$MX ⇌ M^{+} + X^{-} s s K_{sp} = [M^{+}] [X^{-}] = (s) (s) = s^{2} s = \sqrt{K_{sp}} = \sqrt{2.5 \times 10^{- 9}} = 5 \times 10^{- 5}$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App