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The solubility product of a sparingly soluble metal hydroxide M(OH)2 at 298 K is 5 x 10-16 mol3 dm-9. Find the pH value of its aqueous and saturated solution?

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answer is 9.

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Detailed Solution

M(OH)2⇌M+2S+2OH-2S Ksp=[S][2S]2=4S3 S3=5×10−164⇒S=5×10−6M OH−=2×S=1×10−5 ∴ pOH=−logOH−=5 pH=14−5=9

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