First slide

Solubility product(KSP)

Question

The solubility of a sparingly soluble compound ${MX}_{2}$ at $25^{0} C$ is $5.0 \times 10^{- 3} mol / L .$ Its solubility product at that temperature is

Easy

A

$25 \times 10^{- 6}$
B

$5.0 \times 10^{- 11}$
C

$5.0 \times 10^{- 7}$
D

$1.25 \times 10^{- 9}$

Solution

For salts of the type ${MX}_{2}$ ;
$K_{sp} = 4 s^{3} = 4 {(5.0 \times 10^{- 3})}^{3} = 5.0 \times 10^{- 7}$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App