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The solubility of a sparingly soluble salt AxBy, in water at 25°C = 1.4 × 10-4 M. The solubility product is 1.1 × 10-11. The possibilities are
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Correct option is A
Ksp=1.1×10−11=1.4×10−4x+yxx⋅yySo we have x + y = 3 (by comparing values). so, xx⋅yy=1.1×10−111.4×1.4×1.4×10−12=1101.96×1.4=4Hence x = 1,y = 2 or y = 1, x = 2.Similar Questions
The solubility of Ag2CO3 in water at 25°C is 1×10-4 mole / litre. The solubility in 0.01 M Na2CO3 solution is x × 10-5 where x is ________.
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