First slide

Solubility product(KSP)

Question

The solubility of $A_{2} X_{5}$ is x mole ${dm}^{- 3} .$ Its solubility product is

Moderate

A

$36 x^{6}$
B

$64 \times 10^{4} x^{7}$
C

$126 x^{7}$
D

$1.25 \times 10^{4} x^{7}$

Solution

$A_{2} X_{5} ⇌ 2 A^{+ 5} + 5 X^{- 2}$
$K_{SP} = {[A^{+ 5}]}^{2} {[X^{- 2}]}^{5} = {(2 x)}^{2} \times {(5 x)}^{5} = 4 x^{2} \times 3125 x^{5} = 12500 x^{7} = 1.25 \times 10^{4} x^{7}$

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