Questions
A solution of acetic acid is 1.0% ionized. Determine the molar concentration of acid and also the
detailed solution
Correct option is A
CH3COOHC - Cα ⇌ CH3COO-Cα + H+Cα where ‘C’ is the concentration of the acid and α is the degree of dissociation.Ka=Cα×CαC(1-α) As α is very small can be neglected in the denominator Ka=Cα2 Ka = 1.8 × 10-5= Cα2∴ 1.8 × 10-5= C.0.012or C=1.8 × 10-5 × 104 = 1.8 × 10-1MH+ = Cα or H+ =1.8 × 10-1 × 0.01 =0.18 × 0.01=0.0018 M or 1.8 × 10-3 MSimilar Questions
The hydrogen ion concentration in weak acid of dissociation constant and concentration c is nearly equal to
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