A 5% solution of can sugar (molar mass = 342) is isotonic with 1% of a solution of an unknown solute. The molar mass of unknown solute in g/mol is

Two solutions are said to be isotonic, they have the same molar concentration. Therefore, Concentration of cane sugar = Concentration of an unknown solute [X] π1=π2C1ST=C2ST C1=C2m2= 3425 m2=68.4grw1m1×1000V1In ml=w2m2×1000V2In ml 5342×1000100=1m2×1000100m2=3425m2=68.4gr