First slide

Conductivity , Molar conductivity and Equivalent Conductivity

Question

A solution of concentration 'C' g equiv/litre has a specific resistance R. The equivalent conductance of the solution is

Easy

A

$\large \frac{R}{C}$
B

$\frac{C}{R}$
C

$\frac{{1000}}{{RC}}$
D

$\frac{{1000R}}{C}$

Solution

${\lambda _{eq}}\left( {CGS} \right) = \kappa \left( {CGS} \right) \times \frac{{1000}}{N}$

$we\;know\;\;\kappa = \frac{1}{R}$
${\lambda _{eq}}\left( {CGS} \right) = \frac{{1000}}{{RC}}$

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