A solution consists of 0.2 M NH4OH and 0.2 MNH4Cl . If Kb of NH4OH is 1.8×10−5 , the [OH−] of the resulting solution is

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0.9×10−5 M

1.8×10−5 M

3.2×10−5 M

3.6×10−5 M

answer is B.

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Detailed Solution

POH=PKb+log[S][B]=PKb [OH−]=Kb=1.8×10−5

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