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Q.

A solution containing 2.675 g of CoCl3.6NH3 (molar mass = 267.5 g mol-1) is passed through a cation exchanger. The chloride ions obtained in solution were treated with excess of AgNO3 to give 4.78 g of AgCl (molar mass = 143.5 g mol-1). The formula of the complex is (Atomic mass of Ag = 108 u)

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a

[Co(NH3)6]Cl3

b

[CoCl2(NH3)4]Cl

c

[CoCl3(NH3)3]

d

[CoCl(NH3)5]Cl2

answer is A.

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Detailed Solution

Mole of CoCl3.6NH3=2.675267.5=0.01 molAgNO3(aq)+Cl−(aq)→AgCl↓(white)+NO3−(aq)Mole of AgCl=4.78143.5=0.03 mol0.01 mol CoCl3.6NH3 gives = 0.03 mol AgCl∴ 1 mol CoCl3.6NH3 ionises to give = 3 mol Cl−Hence, the formula of compound is [Co(NH3)6]Cl3
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