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Q.

A solution containing 30 g of non-volatile solute in exactly 90 gm water has a vapour pressure of 21.85 mmHg at 25oC. Further 18 g of water is then added to the solution. The resulting solution has a vapour pressure of 22.15 mmHg at 25oC. Calculate the molecular weight of the solute

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a

74.2

b

75.6

c

67.83

d

78.7

answer is C.

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Detailed Solution

We have, po−21.8521.85=30×1890×m, for I case  .....(i)wt. of solvent =90+18=108 gmpo−22.1522.15=30×18108×m, for II case   .....(ii)By eq. (1) pom−21.85m=21.85×6=131.1By eq. (2) pom−22.15m=22.15×5=110.75On doing (1)-(2)0.30m=20.35m=20.350.30=67.83
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