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Q.

A solution containing 28 g of phosphorus in 315 g CS2(b.p. 46.3oC) boils at 47.98oC. If Kb for CS2 is 2.34 K kg mol−1. The formula of phosphorus is (at. mass of P = 31).

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a

P6

b

P4

c

P3

d

P2

answer is B.

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Detailed Solution

ΔTb=mKb=wM×1000W×KbΔTb=47.98−46.3=1.681.68=28M×1000315×2.34M=28×1000×2.34315×1.68=123.73Atomicity = Mol.wt.At.wt.=123.7331=3.99~ 4.0So, Molecule is =P4
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