First slide

Theory of dilute solutions

Question

A solution containing 8.6 g urea in 1 L was found to be isotonic with a 5% (weight/volume) solution of an organic non-volatile solute. The molecular weight of latter is

Moderate

A

348.9
B

34.89
C

3489
D

861.2

Solution

For two non-electrolyte solutions, if isotonic C₁= C₂.
$∴ \frac{8.6}{60 \times 1} = \frac{5 \times 1000}{M w_{2} \times 100} \Rightarrow M w_{2} = 348.9$

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