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A solution contains 0.20 M CH3COONa and 0.10 M CH3COOH, Ka for CH3COOH is 1.8 x 10-5. Concentration of [H+] in mol L-1 in the solution is x x 10-6. What is the value of x?

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answer is 9.

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Detailed Solution

CH3COOH⇌CH3COO−+H+ Ka=CH3COO−H+CH3COOH ∴ H+=KaCH3COOHCH3COO−=1.8×10−5×0.10.2 H+=9×10−6⇒x=9

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