A solution contains 10 mL of 0.1 N NaOH and 10 mL of 0.05 M H2SO4, pH of this solution is

Given, for NaOH, V = 10 mL, N = 0.1N For H2SO4,V=10mL,N=0.05N  Milliequivalents of NaOH=10×0.1=1  Milliequivalents of H2SO4=10×0.05×2=1 H2SO4+2NaOH⟶Na2SO4+H2O ∴ The pH of solution =7 (neutral)