In a solution of CuSO4  how much time will be  required to precipitate 2 g copper by 0.5 ampere current?

Wt. of Cu = 2g, Current, i= 0.5 ampere; t = time is sec= ?;Z (= electrochemical equivalent) = g. eq. wt. of Cu96500Z=63.52×96500According to Faraday's first law of electrolysis: W=it;t=WZit=2g×2×96500C63.5g×0.5 ampere =12157.48sec.