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Q.

A solution has 1 : 4 mole ratio of pentane to hexane. The vapour pressure of pure hydrocarbons at 20oC are 440 mmHg for pentane and 120 mmHg for hexane. The mole fraction of pentane in vapour phase would be:

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a

0.786

b

0.549

c

0.478

d

0.200

answer is C.

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Detailed Solution

Total pressure of solution  PS=PC5H12o.XC5H12o+PC6H140.XC6H14Thus, PS=440×15+120×45=184Therefore fraction of pentane in the vapour phase ,      ⇒   PC5H12o.XC5H12oPS = 88184 =0.478∴XC5H12(g)=0.478
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