A solution has 25% of water, 25% ethanol and 50% acetic acid by mass. The mole fraction of water,ethanol and acetic acid respectively will be

Since 18 g of water = 1 mole 25 g of water =2518=1.38 mole Similarly, 46 g of ethanol = 1 mole 25 g of ethanol =2546=0.55 moles Again, 60 g of acetic acid = 1 mole 50 g of acetic acid =5060=0.83 mole ∴ Mole fraction of water =1.381.38+0.55+0.83=0.50Similarly, Mole fraction of ethanol =0.551.38+0.55+0.83=0.19Mole fraction of acetic acid =0.831.38+0.55+0.83=0.3